We know that studying for your AP exams can be stressful, but Fiveable has your back! We have created a study plan that will help you crush your AP Calculus AB exam. We will continue to update this guide with more information about the 2022 exams, as well as helpful resources to help you score that 5.
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This year, all AP exams will cover all units and essay types. The 2022 AP Calculus AB exam format will be:
The exam is on paper at your school on Monday, May 9, 2022 at 8am, your local time.ย
Before we begin, take some time to get organized. Remote learning can be great, but it also means youโll need to hold yourself accountable more than usual.ย
Make sure you have a designated place at home to study. Somewhere you can keep all of your materials, where you can focus on learning, and where you are comfortable. Spend some time prepping the space with everything you need and you can even let others in the family know that this is your study space.ย
Get your notebook, textbook, prep books, or whatever other physical materials you have. Also create a space for you to keep track of review. Start a new section in your notebook to take notes or start a Google Doc to keep track of your notes. Get yourself set up!
The hardest part about studying from home is sticking to a routine. Decide on one hour every day that you can dedicate to studying. This can be any time of the day, whatever works best for you. Set a timer on your phone for that time and really try to stick to it. The routine will help you stay on track.
How will you hold yourself accountable to this study plan? You may or may not have a teacher or rules set up to help you stay on track, so you need to set some for yourself. First set your goal. This could be studying for x number of hours or getting through a unit. Then, create a reward for yourself. If you reach your goal, then x. This will help stay focused!
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to chat, ask questions, and meet other students who are also studying for the spring exams. You can even build study groups and review material together!ย
Unit 1 is the basic idea of all of Calculus. The limit is the concept that makes everything click. You ask someone what they learned in calculus and they will most likely answer โderivatives and integralsโ. Limits help us to understand what is happening to a function as we approach a specific point. Limits can be one or two sided, but the sides have to match in order for the limit to exist from both directions! Well without the limit, we wouldnโt have either. A major concept used throughout the curriculum and within theorems is continuity. We prove continuity using limits and learn how to do that within this unit. We also learn about the Intermediate Value Theorem and the Squeeze Theorem, although this topic most likely wonโt be directly tested on this yearโs exam, itโs the bread and butter of whatโs to come.ย
๐ฅ Watch these videos:
๐ฐ Read these Fiveable study guides (Especially 1.3-1.16) Unit 2 introduces the first of the 2 major halves of calculus: differentiation, or the instantaneous rate of change of a function. We start off with defining the derivative and applying it to our old friend, the limit. This unit also sets up the rules so that you can figure out the derivative of most simple functions you will find on the FRQ section! We will additionally discuss the difference between average and instantaneous rates of change and how they appear differently. One thing is for sure, you should still follow order of operations!
Average Rate of Change vs Instantaneous Rate of Change
Definition of the Derivative
Estimating The Derivative
Connecting differentiability and continuity. Remember, differentiability implies continuity, but not the other way around! Make sure you know how to tell if a function is differentiable. No cusps or corners, polynomials are always differentiable!
Finding Simple Derivatives using:
Product and Quotient Rules
๐ฅ Watch these videos:
๐ฐ Read these Fiveable study guides.
In Unit 3, we expand on the methods of finding derivatives from Unit 2 in order to evaluate any derivative that Collegeboard can throw at you! This section includes the very important chain rule. Implicit differentiation is a big take away from this unit as well. It allows us to find derivatives of any variable when we may be finding the derivative with respect to something else.
๐ฅ Watch these videos:
The Chain Rule: The chain rule, used to evaluate the derivative of composite functions, is very important!
๐ฐ Read these Fiveable study guides. Unit 4 allows you to apply the derivative in different contexts, most of which have to do with different rates of change. You will also learn how to solve problems containing multiple rates, how to estimate values of functions, and how to find some limits you may not have known how to solve before! Related rates is a very popular topic in the FRQ section of the exam. It is very important you label every variable you use! Limits that you didnโt know how to solve can now be solved using LโHospitalโs rule, but make sure you know the requirements!
One special type of related rate is that of a cone. You should practice a related rate problem with a cone, because it is necessary to write r, the radius, in terms of h before differentiating.
LโHopitalโs Rule
When using LโHospitalโs rule, we have a few things we need to remember! To apply LโHospitalโs rule, your limit needs to be in one of two forms: 0/0 or โ/โ. To show this in a free response question, you need to show the limits in the numerator and the denominator go to either 0 or infinity separate from each other, then you can use LโHospitalโs rule, which says: xaf(x)g(x)=xaf'(x)g'(x).
๐ฅ Watch this video:
๐ฐ Read these study guides (Emphasize 4.2, 4.5-4.7) Unit 5 continues our discussion on the applications of derivatives, this time looking at graphs and how the value of the first and second derivatives of a graph influences its behavior. We will review two of the three existence theorems, the mean and extreme value theorems. Weโll also learn how to solve another type of problem commonly seen in the real world (and also on FRQ problems): optimization problems.
Two of the three Existence Theorems
Mean Value Theorem
In order to use the Mean Value Theorem, the functions must be continuous on a closed interval and differentiable on that same interval, but open. Once you can say for sure that these things are true, the mean value theorem tells us that there must be a point in that interval where the average rate of change equals the instantaneous rate of change, or the derivative, at a point within the interval. f'(c)=f(b)-f(a)b-a.
Extreme Value Theorem
Increasing/Decreasing Functions and The First Derivative
Local and Global Extrema
Concavity, Inflection Points, and The Second Derivatives
If the second derivative is positive, the function will be concave up. If the second derivative is negative, the function will be concave down. Whenever the second derivative changes sign, there will be an inflection point, a change in concavity, on the original function.
Curve/Derivative Sketching
Optimization Problems
These are also known as applied maximum and minimum problems. They are problems about finding an absolute maximum and an absolute minimum in an applied situation. When trying to find an absolute max or min, you must find all critical points (f'(x)=0 or undefined). Then plug those and the endpoints into the original function to find out which has the highest or lowest value, depending on what you are looking for.
Concavity: Using the second derivative to find concavity
๐ฐRead these Fiveable study guides.
Unit 6 introduces us to the integral! We will learn about the integral first as terms of an area and Reimann sums, then working into the fundamental theorem of calculus and the integral's relationship with the derivative. We will learn about the definite integral and the indefinite integral. We will additionally learn about methods of integration from basic rules to substitution. In some cases the integral is called the antiderivative, and if f is the function, then F would be the antiderivative of that function.
Approximating an integral as an area
When given a graph, we can find the area under the curve and between the x axis to find the integral. However, if an area is underneath the x-axis, that would be considered negative.
Riemann Sums
A way of evaluating an area under a curve by making rectangles to find the area of an adding them up. This is useful with a table of values or with a curve that we do not know the exact area of its shape. There are four kinds: Left, Right, Midpoint, and Trapezoidal sum. Depending on the function, these may be over or under estimates of the actual area.ย
Students should also be able to write a Riemann sum in summation notation and integral notation.
The Fundamental Theorem of Calculus
Definite vs. Indefinite Integrals
Integrals must always include a dx (if not x, whichever variable you are using) at the end.ย
If an integral is indefinite, it has no bounds. This means it cannot be evaluated using the fundamental theorem of calculus. Instead, we add on a +C, to make it know that there could have been a constant at the end of the function, and that there are lots of possibilities for what that constant would be.ย
Definite integrals have bounds and we use the fundamental theorem of calculus often with them. The bounds let us know the endpoints of the integral, or in terms of a graph, what two points we are finding the area under the curve between.ย
Integral Rules
U-Substitution
When you have a composition of functions in an integral, it is necessary to use u-substitution to make sure you are integrating each part. It is usually the inside function which is chosen. Sometimes it can be hard to tell. You will know once you try! If you find yourself going in circles and needing to substitute more, I would try using a different piece of the function as u.ย
๐ฅ Watch these videos:
๐ฐ Read these Fiveable study guides. Differential Equations
Modeling - If you are given information, can you write a differential equation from it?ย
Verifying Solutions - Being able to plug in given information and deduce if the solution is true.ย
Separation of variables
This appears often in the FRQ section. Students are given a differential equation and need to put all of the terms for one variable on one side and for the other variable on the other, then they integrate both sides and solve for y, usually y, but really whichever the dependent variable it.ย
NOTE: If you skip the step of separating variables on AP exams in the past, they have offered you no credit for the rest of that section of the problem.ย
Using initial conditions
Once you have done your separation of variables, donโt forget to have a +C! This is where the initial condition comes in. You plug in the terms given from x and y in your initial condition, then you solve for C, rewriting the function at the end with C plugged in!
Slope fields
Slope fields are coordinate planes of 1 by 1 sections of slopes at each x and y value. If given a differential equation and asked to find a slope field, you plug in an x and y pair into the differential equation, the value it outputs is the slope at the point, and is the steepness you use to draw a line at that particular pair.ย
๐ฅ Watch this video:
๐ฐRead these Fiveable study guides.
Unit 8 teaches us more useful applications of the integral as we enter the 3D graph world! We learn how to find the average value of a function and the particle motion according to an integral. We also use cross sections and disks and washers to find volume of shapes as functions are revolved around either a vertical or horizontal line. We put our spatial reasoning and geometry skills to use in this section.ย
Average Value of a function
Position, Velocity, Acceleration
Position is the integral of velocity, and velocity is the integral of acceleration! If you take the absolute value of velocity, you are able to find speed.ย
Distance is the integral of the absolute value of velocity
Displacement is the integral of velocity
To remember this, I think about a track! After one lap around, your distance is 400m, but your displacement is 0. Make sure if you are asked for distance, you remember to use absolute value!
Finding area between curves
If given two curves on a coordinate plane and endpoints, students should be able to integrate those functions, either with respect to the x or y axis, in order to determine the area between them. When talking about the x axis, all functions should be in terms of x, the bounds should be in terms of x, and it will be the integral of the upper functions minus the lower. When talking about with respect to the y-axis, all functions should be in terms of y, the bounds should be in terms of y, and it will be an integral of an outer function minus the inner.
Finding the area between curves that intersect at more than two points.ย
Sometimes, your function will have different parts where you may need to split the area and add your answers together, because the upper functions changes, or another function changes.ย
When in doubt, break it up into pieces you know how to work with, and add those together.ย
Area under the x axis is already accounted for as negative when evaluating using an integral, so donโt worry about that!
Volumes of cross sections
When using cross sections, you integrate the area of whatever shape is given to you (this could be a square, rectangle, triangle, or semicircle).ย
You will integrate the area on a given interval, but it is important that you interpret the function for the variable in the shape that it represents.ย
If it says perpendicular to the x-axis, all should be in terms of x.
Perpendicular to the y-axis, all should be in terms of y.ย
Volumes by disks and washers
In this case we are integrating an area again, but this time the shape will always be a circle, so we will always be using the area formula for a circle. The variable that changes here is r, the radius, which you can interpret using the function.ย
If the rotation is around just the x axis, all should be in terms of x (bounds and functions) and the radius will be your function.ย
If the rotation is around just the y axis, all should be in terms of y (bounds and functions) and the radius will be your function.
If it is rotated around any other vertical or horizontal line, you may need to add or subtract value from your function to find the radius.ย
A washer is when two functions are used, and you must subtract out the volume the inner function would have added into your total volume to account for the missing piece.ย
๐ฅ Watch these videos:
๐ฐRead these Fiveable study guides.