4 min read•january 9, 2023

Josh Argo

Jed Quiaoit

As we finished out on Section 9.4, we have set up the **test** **for slope** of a regression model, now we have to calculate our test statistics and make our conclusion. 🔥

If the assumptions of a linear regression model are satisfied and the null hypothesis is true, the distribution of the slope estimate is a **t-distribution**. Specifically, the slope estimate follows a t-distribution with *n-2* degrees of freedom, where n is the sample size. This follows from the Central Limit Theorem and the fact that the slope estimate is a linear combination of the observations.

The first thing we need to calculate is our critical value (or **t-score**). Our t-score can tell us how far away from the mean (null slope value) our sample is, so it gives us a scale to see how close our sample is to the expected slope value. ⛰️

The formula to compute our t-score is similar to any other critical value. We must take our observed value, subtract the expected value and then divide the result by the standard deviation.

In this case, we are going to base our t-score off of our degrees of freedom being *n-2*. When there is only one parameter we are testing, we will use *n-1* as our degrees of freedom.

The next, and most important statistic that we need to calculate is the **p-value. **Our p-value is the probability that our particular slope occurs if we assume the null slope (usually 0). 🚗

In the example above, our t score came out to be 2.0791 with 21 degrees of freedom. Therefore, since we are performing a two-tailed test, our p-value comes out to be 0.5 (typically your t score and p-value don’t come out to be exactly our significance level). Therefore, there is approximately a 5% chance of obtaining our given sample, assuming that the null slope of 0 is true. A 5% chance of something happening by random chance is pretty low, therefore, we would reject our null hypothesis in favor of the alternate due to the evidence from our sample.

Once you have your t-score and p-value from your calculations, you are ready to conclude your test. As in with any other inference procedure you have performed, your conclusion is primarily based on your p-value that was obtained from your t-distribution and t-score. 🎆

If the p is lower than your significance level:

*"Since our p value is less than our significance level, we reject our Ho. We have significant evidence that the true slope of the regression line between ________ and ______ is (value in alternate hypothesis, usually not 0)."*

If the p is not lower than your significance level:

*"Since our p value is more than our significance level, we fail to reject our Ho. We do not have significant evidence that the true slope of the regression line between ________ and ______ is (value in alternate hypothesis, usually not 0)."*

For more practice on this concept and to see a problem worked through completely, move on to Section 9.6!

You are a researcher studying the relationship between income and happiness. You collect data on income and happiness scores for a sample of 50 individuals. You want to test whether there is a statistically significant linear relationship between these two variables. 😀

You decide to use a t-test for the slope of the regression line to test the following null and alternative hypotheses:

You compute the t-statistic for the slope and find that it has a value of 2.5. The degrees of freedom for the t-distribution are 48 (since the sample size is 50 and there are two variables).

Based on the t-statistic and the degrees of freedom, you compute the p-value for the test. The p-value is the probability of obtaining a t-statistic as extreme as or more extreme than the observed t-statistic, given that the null hypothesis is true.

After performing the t-test, you find that the p-value is 0.01. You use a significance level of 0.05.

In this case, the p-value of 0.01 is less than the significance level of 0.05, so you would reject the null hypothesis that there is no linear relationship between income and happiness. This indicates that there is sufficient evidence to support the alternative hypothesis that there is a linear relationship between these two variables.

Your reasoning for rejecting the null hypothesis would be based on the fact that the p-value is less than the significance level. The p-value represents the probability of obtaining a t-statistic as extreme as or more extreme than the observed t-statistic, given that the null hypothesis is true. If this probability is low, it suggests that the observed t-statistic is unlikely to have occurred by chance, and therefore the null hypothesis is likely to be false. In this case, the low p-value of 0.01 indicates that the observed t-statistic of 2.5 is unlikely to have occurred by chance, and therefore the null hypothesis should be rejected.

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